Find the molarity of a 8.9M KOH solution if 76 ml of solution is diluted to 171 ml? 3.96m

20.03M

0.25m

3.96M
H m pls​

3.96 M

Explanation:

Step 1: Given data

Step 2: Calculate the concentration of the diluted solution

We can calculate the concentration of the diluted solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 8.9 M × 76 mL/171 mL = 3.96 M

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally