Will give brainliest thanks. Part 1. A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equation to determine the mass of NaCl that reacted with F2 at 280. K and 1.50 atm.

F2 + 2NaCl → Cl2 + 2NaF

Part 2. Explain how you would determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP.

PV = nRT. and solving for n (moles F2) we have

n = PV/RT = (1.50 atm)(15.0 L)/(0.0821 Latm/Kmol)(280K)

n = 0.9788 moles F2

mass NaCl = 0.9788 mol F2 x 2 mol NaCl x 58.4 g/mol = answer

To find mass NaCl at STP just substitute 1 atm for pressure and 273K for temperature in the above equation and follow the rest of the calculations above.

the answer is b. dilution

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72