Chemistry, 17.04.2021 01:30 luje

Calculate ΔH in kJ/mol for the reaction N2O5(g) → N2O4(g) + 1/2 O2(g) using these reactions:

2 N2O5(g) → 2 N2(g) + 5 O2(g) ΔH = -38.7 kJ/mol
1/2 N2(g) + O2(g) → NO2(g) ΔH = 32.7 kJ/mol
N2O4(g) → 2 NO2(g) ΔH = 51.8 kJ/mol

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Calculate ΔH in kJ/mol for the reaction N2O5(g) → N2O4(g) + 1/2 O2(g) using these reactions:
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More questions: Chemistry Another questions

Calculate ΔH in kJ/mol for the reaction N2O5(g) → N2O4(g) + 1/2 O2(g) using these reactions: 2 N2O5(g) → 2 N2(g) + 5 O2(g) ΔH = -38.7 kJ/mol 1/2 N2(g) + O2(g) → NO2(g) ΔH = 32.7 kJ/mol N2O4(g) → 2 NO2(g) ΔH = 51.8 kJ/mol

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Another question on Chemistry

Calculate ΔH in kJ/mol for the reaction N2O5(g) → N2O4(g) + 1/2 O2(g) using these reactions:

2 N2O5(g) → 2 N2(g) + 5 O2(g) ΔH = -38.7 kJ/mol
1/2 N2(g) + O2(g) → NO2(g) ΔH = 32.7 kJ/mol
N2O4(g) → 2 NO2(g) ΔH = 51.8 kJ/mol