What product(s) are expected in the ethoxide-promoted β-elimination reaction of 2-bromo-2,3-dimethylbutane? omit ions, salts, and ethanol from your response.

There are two possible products from this elimination: 
-2,3-dimethylbut-1-ene 
-2,3-dimethylbut-2-ene 

As the base is relatively unhindered, the reaction will form the Saytzeff product as the major product. The Saytzeff product is the most substituted alkene which is more stable due to hyperconjugation. In this reaction the Saytzeff product is 2,3-dimethylbut-2-ene.

Yes she is correct. the answer is completely correct

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer