When 9.8 mol fe react with 11.5 mol hcl, what is the limiting reactant and how many moles of h2 can be formed?
unbalanced equation: fe + hcl yields fecl3 + h2
hcl is the limiting reactant, and 3.83 mol h2 can be formed
fe is the limiting reactant, and 4.90 mol h2 can be formed
hcl is the limiting reactant, and 5.75 mol h2 can be formed
fe is the limiting reactant, and 14.7 mol h2 can be formed

To answer the question, we first balance the given chemical reaction. Such that,
                           2Fe + 6HCl --> 2FeCl3 + 3H2
For every 2 mols Fe, 6 mols HCl is needed. From the given amounts, 
         9.8 mols of Fe needs 29.4 mols HCl. Since, there will be an anticipated lack of HCl, the limiting reactant is HCl. For 11.5 mols HCl, only 3.83 mols Fe is needed. This reaction will yield 5.75 mols H2. The answer is the third choice. 

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