Achemist dissolves 1 mol nacl in a 2.0-kg sample of water, then dissolves 1 mol sucrose in another 2.0-kg sample of water. why does the nacl solution have the lower freezing point?

Due to more number of solute particles in NaCl, it will have lower freezing point.

Explanation:

Lowering in freezing point is a colligative property. It depends upon the number of solute particles.

Now when we dissolve NaCl and sucrose in equal moles in two same mass of samples of water, the number of particles in NaCl solution is more as compared to sucrose.

NaCl being an electrolyte will dissociate into its ions (Na⁺ and Cl⁻). Thus each mole of NaCl will give more than one mole of solute particles.

Sucrose being a non electrolyte, will not dissociate and thus its one mole will give only one mole of solute particles.

Depression in freezing point of NaCl will be thus more than that of sucrose solution.

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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