Asample of propane, a component of lp gas, has a volume of 35.3 l at 315 k and 922 torr. what is its volume at stp (r = 0.08206 l • atm/k • mol, 1 atm = 760 torr)?

Answer : The volume of gas at STP is, 37.12 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 922 torr = 1.213 atm

conversion used : (1 atm = 760 torr)

= final pressure of gas at STP = 1 atm

= initial volume of gas = 35.3 L

= final volume of gas at STP  = ?

= initial temperature of gas = 315 K

= final temperature of gas at STP = 273 K

Now put all the given values in the above equation, we get:

Therefore, the volume of gas at STP is, 37.12 L