What is the molarity of the solution made by dissolving a 5.67 g of potassium chloride in enough water to make 100 ml of the solution

There are a number of ways to express concentration of a solution. This would include the molarity. It is expressed as the number of moles of solute per volume of the solution. For example, we are given a solution of 2M NaOH this describes a solution that has 2 moles of NaOH per 1 L volume of the solution. We calculate as follows:

molarity = 5.67 g KCl ( 1 mol KCl / 74.55 g KCl ) / (100 mL solution) ( 1 L / 1000 mL ) = 0.76 mol KCl / L solution or 0.76 M

Therefore, the molarity of the given solution above would be 0.76 M.

Hno3(aq) → h+(aq) + no3−(aq). picture ii best represents the strong acid hno3. strong acids are strong electrolytes