How many grams of ticl4 are needed to produce 14.7 g of titanium?

This is a stoichiometry problem. The reaction is Ti + 2Cl2 --> TiCl4. You start with a mass of titanium, and you need to end up with mass of titanium (IV) chloride. The basic plan for any stoichiometry problem is Mass of A --> Moles of A --> Moles of B --> Mass of B. So we have Mass of Ti --> Moles of Ti --> Moles of TiCl4 --> Mass of TiCl4, and you get 14.7 g Ti * 1 mol Ti/47.88 g Ti * 1 mol TiCl4/1 mol Ti * 189.68 g TiCl4 / 1 mol TiCl4 = 58.2 g TiCl4. So your answer is 58.2 g

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

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