What is the molarity of a soln containing 0.5 mols NaOH in 5 L ?

Explanation:

1 mol NaOH = atomic mass of Na + atomic mass of O + atomic mass of H = 23 + 16 + 1 = 40g.

0.5 g NaOH = 0.5 / 40 mol NaOH = 0.0125 mol of NaOH

500 ml of water = 500/1000 = 0.5 L

Now, molarity = number of moles of solute / total volume of the solvent

= 0.0125 / 0.5 = 0.025 mol/L.

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