Two billiard balls having masses of 0.2 kg and 0.15kg approach each other. The first ball having a velocity of 2m/s hit the second ball which is at rest. What will be the velocity of the first ball if the second ball travels at 1.5 m/s after collision?

The velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.

Explanation:

Given: = 0.2 kg,       = 0.15 kg

= 2 m/s,     = 0 m/s,       = ?,           = 1.5 m/s

Formula used is as follows.

where,

v = velocity before collision

v' = velocity after collision

Substitute the values into above formula as follows.

Thus, we can conclude that the velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.

2b2t

explanation:

2b2t