Iron reacts with copper (I) sulfate to produce copper and iron (II) sulfate. If 4.32x10^25 particles of copper (I) sulfate react, how many moles of copper will be produced?
Fe + Cu2504 --> FeSO4 + 2Cu

143.48 moles of copper will be produced.

Explanation:

We are given:

Number of particles of copper (I) sulfate =

According to the mole concept:

number of particles is contained in 1 mole of a compound

So, number of particles will be contained in = of copper (I) sulfate

The given chemical equation follows:

By the stoichiometry of the reaction:

If 1 mole of copper (I) sulfate produces 2 moles of Cu

So, 71.74 moles of copper (I) sulfate will produce = of Cu

Hence, 143.48 moles of copper will be produced.

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied