(b) Using 25.0 cm of aqueous sodium hydroxide, 2.24 mol / dm'3, 3.86 g of crystals were
obtained. Calculate the percentage yield.
2NaOH + H2SO—>Na2SO4 + 2H2O
Na2SO4 + 10H20—>Na S04.10H2O
I
Number of moles of NaOH used =
Maximum number of moles of Na2S04.10H2O that could be formed =
Mass of one mole of Na2S04.10H20 = 322g
Maximum yield of sodium sulphate-10-water =
Percentage yield =
Answers: 1
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(b) Using 25.0 cm of aqueous sodium hydroxide, 2.24 mol / dm'3, 3.86 g of crystals were
obtained. C...
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