PLEASE HELP , 50 points!

Write the electron configuration of a -2 ion with 16 protons.

1s^2 2s^2 2p^6 3s^2 3p^6

Explanation:

Number of electrons = Number of protons. Originally, sulfur has 16 protons, but the question asks states 2- ions. So S^(2-), or a total of 18 protons. Follow the rules, and make sure the exponents add up to 18. 2 + 2 + 6 + 2 + 6 = 18 electrons.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.