In an experiment, 0.250 moles of propanoic acid, CH3CH2COOH were mixed with 0.150 moles of ethanol and the mixture was allowed to reach equilibrium. Given the total volume is 250 cm3. CH3CH2COOH (aq) + C2H5OH (aq) ⇌ CH3CH2COOC2H5 (aq) + H2O (l) At equilibrium, 0.125 moles of propanoic acid remained. Calculate the value of Kc for the above reaction.

Answer asap need by wednesday morning explain how a buffer works, using an ethanoic acid/sodium ethanoate system including how the system resists changes in ph upon addition of a small amount of base and upon addition of a small amount of acid respectively. include the following calculations in your i. calculate the ph of a solution made by mixing 25cm3 0.1m ch3cooh and 40cm3 0.1m ch3coo-na+. [ka = 1.74 x 10-5 m] ii. calculate the ph following the addition of a 10cm3 portion of 0.08 m naoh to 500cm3 of this buffer solution. iii. calculate the ph following the addition of a 10cm3 portion of 0.08 m hcl to 200cm3 of the original buffer solution.