What is the weight of a 2000 kg satellite in a geosynchronous orbit?

Refer to the diagram shown below.

In geosynchronous orbit, the satellite makes one circular revolution at the equator in 1 day.

From tables, obtain
r = 42,164 km = 4.2164 x 10⁷ m, the earth's radius
g = 9.8 m/s², acceleration due to gravity.

Note that 1 day = 86400 s
The angular velocity of rotation is
ω = (2π)/86400 = 7.2722 x 10⁻⁵ rad/s

The centripetal acceleration on the satellite is
a = rω²
   = (4.2164 x 10⁷ m) * (7.2722 X 10⁻⁵ rad/s)²
   = 0.223 m/s²

The weight of the 2000 kg satellite is
W = m(g - a)
    = (2000 kg) * (9.8-0.223 m/s²)
    = 19154 N
    =  19.154 kN

  19 kN  (nearest integer)

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !

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