How many grams of mercury are needed to react completely with 157g of sulfur to form hgs?

983 g

Explanation:

Let's consider the following reaction.

Hg + S → HgS

The molar mass of S is 32.07 g/mol. The moles corresponding to 157 g are:

157 g × (1 mol/32.07 g) = 4.90 mol

The molar ratio of Hg to S is 1:1. The moles of Hg that react are 4.90 moles.

The molar mass of Hg is 200.59 g/mol. The mass corresponding to 4.90 moles is:

4.90 mol × (200.59 g/mol) = 983 g

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