Which equation represents the reduction half-reaction for this redox equation? mg + cuso4 mgso4 + cu a. cu cu b. cu + 2e- cu c. cu cu + 2e- d. cu + 3e- cu,

The oxidation number of Cu in CuSO₄ is +2 and 0 in Cu, the free elemental form. As the oxidation of Cu decreases from +2 to 0, we are looking at the reduction half-reaction for the given redox reaction:

Cu²⁺ + 2e⁻ → Cu

The correct answer is option B.

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explanation: