How many molecules (not moles) of nh3 are produced from 7.26×10−4 g of h2?

The balanced chemical equation for the formation of NH₃ is given below 
N₂ + 3H₂ --> 2NH₃
stoichiometry of H₂ to NH₃ is 3 : 2
Mass of H₂ reacted - 7.26 x 10⁻⁴ g
number of H₂ moles - 7.26 x 10⁻⁴ g / 2 g/mol = 3.63 x 10⁻⁴ mol
when 3 mol of H₂ reacts - 2 mol of NH₃ is formed 
Therefore when 3.63 x 10⁻⁴ mol of H₂ reacts - 2/3 x 3.63 x 10⁻⁴ mol of NH₃ 
Number of NH₃ moles formed - 2.42 x 10⁻⁴ mol
Since 1 mol of NH₃ is made of 6.022 x 10²³ molecules 
NH₃ molecules formed - 6.022 x 10²³ molecules /mol x 2.42 x 10⁻⁴ mol
                                   = 1.46 x 10²⁰ molecules of NH₃ formed 

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