The structure below represents a tetrahedral alkoxide-ion intermediate formed by addition of a nucleophile to a carboxylic acid derivative. -+labels in the window below, draw both the starting acid derivative and the ultimate carboxylic acid derivative product. do not include the product formed by the leaving group.

Let's suppose the tetrahedral Alkoxide Ion is as given below in reaction (*).

In this reaction the starting carboxylic acid derivative is Benzoyl Chloride.

Benzoyl Chloride when reacted with Methaneamine forms Tetrahedral Alkoxide Ion, The negative charge migrates to carbon forming double bond and the chloride ion (good leaving group) leaves and abstract proton from Nitrogen atom to neutralize it.
So,
The Final product is Methylbenzamide (Amide) which is also a derivative of carboxylic acid.

Reaction is shown below,

It is 4.92 e-4 sorry if i am wrong