If δh = -70.0 kj and δs = -0.400 kj/k , the reaction is spontaneous below a certain temperature. calculate that temperature.

According to this formula, when:

ΔG = ΔH  - T*ΔS

when the reaction is thermodynamically spontaneous ΔG < 0 

∴ ΔH - T* ΔS = 0 

∴T*ΔS = ΔH

∴ T = ΔH / ΔS

when we have:

ΔH = -70KJ

and ΔS = -0.4 KJ/K

So by substitution:

T =  -70KJ /- 0.4

  =  175 K 

∴the certain temperature below which the reaction will be thermodynamically spontaneous is 175 K  

The answer would be c. fish