Computers and Technology, 22.04.2020 00:31 mashejaj
One reason that naive sharing fails in the echo server example is that the read–update–write sequence needed for C instruction counter += n may not be a single instruction in machine code. To how many x86-64 instruction(s) does this C instruction translate, when no complier optimizations are used?
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One reason that naive sharing fails in the echo server example is that the read–update–write sequenc...
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