Internet service providers (isp) need to resolve customer problems as quickly as possible. for one isp, past data indicates that the likelihood is 0.80 that customer calls regarding internet service interruptions are resolved within one hour. out of the next 10 customer calls about interrupted service, what is the probability that exactly 7 will be resolved within one hour?

To solve this problem, we make use of the binomial probability formula. That is:

P = [n! / (n – r)! r!] p^r * q^(n – r)

where,

n is the total number of customer calls = 10

r is the number of resolved customer calls = 7

p is the probability of resolving in one hour = 0.80

q is 1 – p = 0.20

Therefore,

P = [10! / (10 – 7)! 7!] 0.80^7 * 0.20^(10 – 7)

P = 0.2013 = 20.13%

is this supposed to be a question ?