In a steam power plant, energy is added by heat transfer at a rate of 2100 kw at 680◦c at the boiler, removed at a rate of 1240 kw at 35◦c at the condenser, and the pump power is 75 kw. determine: a. thermal efficiency of power plant b. maximum possible turbine power [kw] (assume same energy transfers at boiler and pump)

a. 94.86%

              b. 2067.06 kW

Explanation: a. Tc = 35 C

                          Th = 680 C

                          Thermal Efficiency (η) = 1 - Tc/Th

                                                          = 1 - 35/680

                                                          = 0.9486

Hence Thermal Efficiency of Plant  = 94.86%

b. Qh = 2100 kW

   Wp = 75 kW

η = (Wt - Wp) / Qh

Wt = (η * Qh) + Wp = (0.9486 * 2100) + 75 = 2067.06 kW

answer:

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explanation: