The surface of an elastic body is loaded by a uniform stress of 2000 psf over an area 30 ft by 60 ft, which has coordinates (0, 0) at the center.
Find:
(a) the vertical stress at a depth of 10 ft below a corner of the loaded area.
(b) the vertical stress at a depth of 20 ft below the center of the loaded area.
(c) the vertical stress at a depth of 30 ft below a point which has coordinates 10 ft greater than those of the corner of the loaded area in the first quadrant (first quadrant is the one with positive x and y coordinates).

q = 1.11 lb  

psf

psf

psf

Explanation:

given data  

uniform stress = 2000 psf  

area = 30 ft by 60 ft  

solution

we get here surface load uniform homogenous soil is express as

q =      ................1

q =

q = 1.11 lb  

and  

now we apply here boussin vertical stress that is at depth 10 ft  

 =        ................2

 psf  

and  

depth at 20 ft will be put value in equation 2  

 psf  

and  

at depth at 30 ft  

depth at 20 ft will be put value in equation 2  

 psf  

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation: