A 1 250 kg car moving at a velocity of 30 km/hr along EDSA is accelerated by a force of 1 700 N. What will be its velocity after 10 seconds? (Neglect friction)

The velocity of the car after 10 s is 78.95 km/hr

Explanation:

Given:

m = 1,250 kg

= 30 km/hr

F = 1,700 N

t = 10 s

Required:

Final velocity

Equation:Force

F = ma

where: F - force

m - mass

a - acceleration

Acceleration

a =

where: a - acceleration

- initial velocity

- final velocity

t - time elapsed

Solution:Solve for acceleration using the formula for force

F = ma

Substitute the value of F and m

(1700 N) = (1250 kg)(a)

a =

a = 1.36 m/s²

Solve for final velocity using the formula for accelerationConvert 30 km/hr to m/s

=

=

Substitute the value of a, and t

a =

Convert to km/hr

=

=

Final answerThe velocity of the car after 10 s is 78.95 km/hr