A 2.00 kg piece of aluminum metal at 75.0 °C is placed in 6.00 liters (= 6.00 kg) of water at 35.0 °C. Determine the final temperature .

T = 46.97 °C

Explanation:

Applying the law of conservation of energy, we get:

Heat Energy Lost by Aluminum Piece = Heat Energy Gained by Water

where,

= mass of water = (Density)(Volume) = (1000 kg/m³)(1 L)(0.001 m³/1 L)

= 1 kg

= mass of auminum piece = 2 kg

= specific heat capacity of water = 4200 J/kg.°C

= specific heat capacity of aluminum = 897 J/kg.°C

= Change in Temperature of Water = T - 35°C

= Change in Temperature of Aluminum Piece = 75°C - T

T = Final Temperature = ?

Therefore,

T = 46.97 °C

answer:

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