The equation x2+px−35=0 has one root that is equal to 7. find the other root and the value of the coefficient p.

For this case we have the following polynomial:
 x2 + px-35 = 0
 We can factor the polynomial.
 Rewriting we have:
 (x-7) * (x + a) = 0
 The value of a is given by:
 -7 * a = -35
 a = 35/7
 a = 5
 Substituting we have:
 (x-7) * (x + 5) = 0
 Therefore, the value of p is:
 p = -7 + 5
 p = -2
 
 the other root is:
 x = -5
 The value of the coefficient is:
 p = -2

(-14+3/2b) - (1+8/2b) = -5 -5/2b(-10+b) + (7b-5) = 8b-15(7/2b-3) - (8+6b) = -5/2b-11(5+2b) + (2b+3/2) = 4b+ 13/2