Find a1 and d for an arithmetic sequence with these terms. a3=-8 and a7=32

We know that
the formula for the arithmetic sequence is
an = a1 + (n - 1)*d
where
a1  is the first term
n is the numbers of terms

for n=3   a3=-8
-8=a1+(3-1)*d> -8=a1+2*d> equation 1

for n=7   a7=32
-32=a1+(7-1)*d> -32=a1+6*d> equation 2

multiply equation 2 by -1> 32=-a1-6*d> equation 3

add equation 1 and equation 3
-8=a1+2*d
32=-a1-6*d

24=-4*d> d=-6
-8=a1+2*(-6)    (substitute the value of d in equation 1)
-8=a1-12> a1=-8+12> a1=4

the answer is
a1=4
d=-6