Given that g(x)=2x^2-5x+5am , find each of the following. a) g(0) b) g(- 1) c) g(4) d) g(-x) e) g(1-t)

A) g(0)=2(0)^2-5(0)+5 // g(0)= 5
b) g(-1)=2(-1)^2-5(-1)+5 // g(-1)= 14
c) g(4)=2(4)^2-5(4)+5 // g(4)= 49
d) g(-x)=2(-x)^2-5(-x)+5 // g(-x)= 9x+5
e) g(1-t)=2(1-t)^2-5(1-t)+5 // g(1-t)= 4t^2-3t+4

It’s 24.6 after you round to the nearest tenths the answer should be 25.0