What is the equation of a line, in general form that passes through point (1,-2) and had a slope of 1/3 3x-y-7=0 x-3y+7=0 x-3y-7=0

Step-by-step explanation:

The equation of line passing from point (a,b) and has slope m is given by :-

Given : Point = (1,-2)

Slope of line=

Now, the equation of a line that passes through point (1,-2) and had a slope of will be :-

Hence, the  equation of a line, in general form that passes through point (1,-2) and had a slope of is

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23