What is the solution to the system of equations 3x+2y=39 5x-y=13

Hiya. I'm going to rewrite the second equation.

By subtracting 5x by both sides, I'll be able to have y by itself:

-y=-5x+13

I'm going to then divide both sides by -1 to get:

y=5x-13.

Then, I'm going to plug that equation into the first equation

3x+2(5x-13)=39

Factor:

3x+10x-26=39

Combine like terms:

13x=65

Divide both sides by 13 to get x by itself to get x=5

Plug this back into the equation of y=5x-13

y=5(5)-13 to get y=12

Solve: 3x + 2y = 39; 5x - y = 13

I will try to solve your system of equations:

5x - y = 13; 3x + 2y = 39

Solve 5x - y = 13 for y:

5x - y + - 5x = 13 + - 5x (add - 5x to both sides):

- y = - 5x + 13

- y/ - 1 = - 5x + 13/ - 1 (Divide both sides by - 1):

y = 5x - 13

Substitute 5x - 13 for y in 3x + 2y = 39

3x + 2y = 39

3x + 2(5x - 13) = 39

13x - 26 = 39 (Simplify both sides of the equation)

13x - 26 + 26 = 39 + 26 (Add 26 to both sides):

13x = 65

13x/13 = 65/13 (Divide both sides by 13)

x = 5

Substitute 5 for X in Y = 5x - 13

y = 5x - 13

y = (5)(5) - 13

y = 12 (Simplify both sides of the equation):

y = 12 and x = 5

Hope that helps ( y = 12 and x = 5).

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation:

answer:   rotate 270° clockwise about (7, 1) and reflect across the line x = 7

step-by-step explanation:

because i took test