During a rock concert, the noise level (in decibels) in front row seats has a mean of 95 db with a standard deviation of 5 db. without assuming a normal distribution, find the minimum percentage of noise level readings within 5 standard deviations of the mean during a rock concert, the noise level (in decibels) in front row seats has a mean of 95 db with a standard deviation of 5 db. without assuming a normal distribution, find the minimum percentage of noise level readings within 5 standard deviations of the mean

We know about Chebyshev's theorem, we can find minimum percentage of noise level readings within 5 s.d. of the mean by using the following formula:-

Here the value of x=5 given in the question.

So

So final answer is 0.96 or 96%.

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950