John commutes each day to work either by train or by bus. the bus pass costs $10 plus $2 per trip. the train costs $15 plus $1.50 per trip. what is the most number of trips john can make before the bus costs more than the train?

10

Step-by-step explanation:

Let n be the no. of trips

Cost of bus pass = $10

Cost of per trip by bus = $2

Cost of n trips by bus 2n

Total cost by Bus= 10+2 n

Cost of Train pass = $15

Cost of per trip by train = $1.50

Cost of n trips by train = 1.50n

Total cost by train = 15+1.50 n

We are supposed to find the most number of trips John can make before the bus costs more than the train

So,

Hence the most number of trips John can make before the bus costs more than the train is 10 .

the slope of the first function is -3. (3/1)

the slope of the second function is 1. (13-10/6-3).

since |-3| is greater than |1|, the function with the steepest slope is the first.

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.