Let f(x) = 8x3 − 22x2 − 4 and g(x) = 4x − 3. find f of x over g of x. 2x2 − 4x − 3 − 13 over quantity 4x minus 3 2x2 − 4x − 3 − quantity of 4 x minus 3 over 13 2x2 − 7x − 1 2x2 − 7x − 5 + quantity of x minus 4 over quantity of 4 x minus 3

Given that and

Question says to find f of x over g of x which simply means divide value of f(x) by value of g(x)

Dividing them gives:

Denominator is already in factored form which can't divide numerator means it can't be simplified more.

Hence final answer is .

other part of question is not clear so i will skip them.

really really sorry if i'm

-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x