Abee flies at 20 feet per second directly to a flower bed from its hive. hthe bee stays at the flower bed for 15 minutes, then flies directly back to the hive at 12 feet per second. it is away from the hive fore 20 minutes total. a. what equation can you use to find the distance of the flowerbed from the hive? b. how far is the flowerbed from the hive?

we are given

A bee flies at 20 feet per second directly to a flower bed from its hive

so, forward speed is

flies directly back to the hive at 12 feet per second

so, backward speed is

It is away from the hive fore 20 minutes total

so,

total time = forward time + backward time + stay time

The bee stays at the flower bed for 15 minutes,

20 =tf+tb+15

now, we can change it into seconds

(a)

we know that

distance between hive and flower bed will remain same

Let's assume

forward time =x

so,

we know that

distance = speed*time

now, we can plug values

now, we can plug values

both distances are same

(b)

now, we can solve above equations and find x

add both sides 12x

now, we can find distance

so, distance between hive and flower bed is 2250 feet.........Answer

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

600,000,000,000, or 6e14

step-by-step explanation: