Arnold is writing a program for a video game for one part of the he uses the rule (x, y) (x+7,y-3) to move points on the screen a. what output does the rule give when the input is (-10,0) b. what output does the rule give when input is(-7,3) c. is the rule a function?

We are given rule

when

input is (x,y)

then output is (x+7 , y-3)

(A)

we are given

input is (-10,0)

so, x=-10 and y=0

now, we can find output

x+7=-10+7=-3

y-3=0-3=-3

so, output is (-3,-3)

(B)

we are given

input is (-7,3)

so, x=-7 and y=3

now, we can find output

x+7=-7+7=0

y-3=3-3=0

so, output is (0,0)

(C)

We know that

x+7 and y-3 are translation rules of function

so, this is function

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.