Aveterinarian wishes to use 132 feet of chain link fencing into two smaller rectangels having the same lengths and same widths. of the total enclosed anrea is 576 square feet, find the dimensions of the enclosed region

to better understand the problem see the attached figure

Let

x-------> the length of one rectangle of the enclosed region

y------> the width of one rectangle of the enclosed region

we know that

the dimensions of the enclosed region are

Length=2x

Width=y

the perimeter of one rectangle is equal to

P=2x+2y

in this problem

the perimeter of the enclosed region is equal to

132=[4x+3y]

132=4x+3y------> equation 1

the area of one rectangle is equal to

A=x*y

in this problem

576=[2x*y] ------> equation 2

Solve the system

132=4x+3y------> equation 1

576=[2x*y] ------> equation 2  

using a graph tool-------> to solve the system equation

see the attached figure

the solution is    

x=24 ft

y=12 ft

therefore

the answer is

the dimensions of the enclosed region are 48 ft * 12 ft

answer: they are supplementary angles

step-by-step explanation: 161+19=180. supplementary angles equal 180 degrees

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)