From a group of 8 men and 7 women, a committee of 6 is chosen. a. in how many ways can the committee be chosen so that the same amount of men and women are chosen?

It is given in the question that from a group of 8 men and 7 women, a committee of 6 is chosen.

And we have to find the number of ways can the committee be chosen so that the same amount of men and women are chosen. That is number of men= number of women =3

Selecting 3 men out of 8 men is 8C3 which is equal to 56.

Selecting 3 women out of 6 women is 6C3 which is equal to 20 .

So the required selection is the product of 56 and 20 that is 1120.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

you already gave the answer

step-by-step explanation: