Write an equation for the quadratic function that has one x-intercept at (-7, 0) and passes through (-4, -18).

The quadratic function has an x-intercept of (-7,0)

and passes through (-4,-18)

The gradient(m) of its graph is (-18 - 0) ÷ (-4 - -7) = -18/3 = -6

Taking a point (x,y) the equation is;

(y - 0) ÷ (x - -7) = -6

y = -6x - 42

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

a. is correct