What is the greatest common factor of 63b^2c^4 and 42b^3c^2

Factor out the GCF of  

21

b

2

c

2

from  

63

b

2

c

4

+

42

b

3

c

2

.

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Factor out the GCF of  

21

b

2

c

2

from each term in the polynomial.

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Factor out the GCF of  

21

b

2

c

2

from the expression  

63

b

2

c

4

.

21

b

2

c

2

(

3

c

2

)

+

42

b

3

c

2

Factor out the GCF of  

21

b

2

c

2

from the expression  

42

b

3

c

2

.

21

b

2

c

2

(

3

c

2

)

+

21

b

2

c

2

(

2

b

)

Since all the terms share a common factor of  

21

b

2

c

2

, it can be factored out of each term.

21

b

2

c

2

(

3

c

2

+

2

b

)

The greatest common factor  

GCF

is the term in front of the factored expression.

21

b

2

c

2

21b^2c^2

Step-by-step explanation:idk to be honest lol

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.