An airplane started at 0 feet. it rose 21000 feet at takeoff. it then descended 4329 feet because of clouds. after the oncoming plane passed, it descended 8453 feet, at what altitude was the plane flying?

The fact that an oncoming plane passed is irrelevant to what we need to find, so we can ignore that.

The math statement it's asking you to solve is this:

0+21000-(4329+8543)

The reason we are adding 4329 and 8543 is to make it easier on the subtraction. Since both of those terms are being subtracted, we can combine them to make our problem one step shorter.

After simplifying the parentheses, we get:

21000-12872

After this it becomes simple subtraction to find the answer.

8128 is the answer, so your answer would be:

The plane is now flying at an altitude of 8,128 feet.

Ur answer is

The plane was flying at 8,218 feet altitude

Step-by-step explanation:

This is easy u start off with 21,000 then subtract as needed

21,000-4329=16,671

16,671-8,453=8,218

So ur answer is 8,218

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.