The length of a rectangle is triple the width. it's perimeter is more than 40m. find the smallest possible values for its length and width.

Given:- the length of a rectangle is triple the width. it's perimeter is more than 40m.

Now, from the given condition we have , where l is the length of the rectangle and b is the width of the rectangle.

Perimeter(P) of a rectangle is given by,

Since perimeter is more than 40 m we have,

8b>40

⇒ b>5 m

since, then

⇒

if we take the integers, the smallest possible values for its length and width , m and b=6 m.

answer: h

step-by-step explanation:

no idea

step-by-step explanation: