What is the factor and product of 3x(x+9)=3x^2+27x

Let's solve your equation step-by-step.

3x(x+9)=3x^2+27x

Step 1: Simplify both sides of the equation.

3x^2+27x=3x^2+27x

Step 2: Subtract 3x^2 from both sides.

3x^2+27x−3x^2=3x^2+27x−3x^2

27x=27x

Step 3: Subtract 27x from both sides.

27x−27x=27x−27x

0=0

All real numbers are solutions.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: