Triangle qrs is a right triangle. complete the similarity statement. δstr ~ δtqrrstsqrrtq

ΔSTR is similar to ΔRTQ

Step-by-step explanation:

Given QRS is a right angled triangle. we have to find the similarity statement ΔSTR ~ Δ__

Let ∠S=x

In ΔSTR, by angle sum property

∠S+∠STR+∠SRT=180°

⇒ ∠SRT=90°-x

In ΔSRQ, by angle sum property

∠S+∠R+∠Q=180°

⇒ ∠Q=90°-x

In ΔSTR and ΔRTQ

∠SRT=∠Q=90°-x     (proved above)

∠STR=∠RTQ           (each 90°)

RT=RT                      (common)

Hence, by AAS rule ΔSTR≅ΔRTQ

∴ ΔSTR is similar to ΔRTQ

Option 4 is correct.

RTQ

Step-by-step explanation:

Let ∠S=a, In ΔSTR, using angle sum property, we have

∠S+∠STR+∠SRT=180°

⇒ ∠SRT=90°-a

Again In ΔSRQ, using angle sum property, we have

∠S+∠R+∠Q=180°

⇒ ∠Q=90°-a

Now, In ΔSTR and ΔRTQ

∠SRT=∠Q=90°-a    (proved above)

∠STR=∠RTQ              (each 90°)

 RT=RT                      (common)

Hence, by AAS rule,

ΔSTR≅ΔRTQ

Thus,  ΔSTR is similar to ΔRTQ

Option 4 is correct.

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct

stops on an even number.