Find the co-ordinates of the vertex of the function y=x²-12x+2 and show your work

vertex = (6, - 34 )

the equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

To obtain this form, complete the square on x² - 12x

• add/subtract (half the coefficient of the x- term )²

y = x² + 2(- 6 )x + 36 - 36 + 2 = (x- 6 )² - 34 ← in vertex form

vertex = (6, - 34 )

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

hope this !

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step-by-step explanation: