Let x={x|x is a whole number less than 15}, y={x|x is a multiple of 3}, z={x|x is a real number greater than or equal to 5.5} what is xny? (1 point) a- {0,3,6,9,12} b- {3,6,9,12,15} c- { -6,-3,0,3,6,9} d- { -6,-3,0,3,6,9,12}

 The correct option is

(A) {0,3,6,9,12}.

Step-by-step explanation:  We are given the following three sets :

X={x|x is a whole number less than 15},

Y={x|x is a multiple of 3},

Z={x|x is a real number greater than or equal to 5.5}

We are to find the set X∩Y.

The elements in the given sets X, Y and Z can be written as follows :

The set X∩Y will contain all the elements that are present in both X and Y.

Therefore, we get

X∩Y = {0,3,6,9,12}.

Thus, (A) is the correct option.

X = { 0, 1, 2, 3, 4, 5, 6, 7, ... , 14 }

Y = { 0, 3, 6, 9, 12, 15, 18, ... }

Z = {x| x ∈ R ∧ x ≥ 5.5 }

X ∩ Y = { 0, 3, 6, 9, 12 }

A

The intersection X ∩ Y, is the set of all things that are members of both X and Y.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116