What value of a satisfies the following equation 5a+53a−1=3 ? select one: a. 0 b. 1 c. 2 d. no real number

5a+53a−1=3

add 1 to each side

5a +53a = 4

58a =4

a = 4/58

a = 2/29

No real number (D)

Step-by-step explanation:

Given the equation 5a+53a-1=3

To get the value of 'a'

First, we will add 1 to both sides to have;

5a+53a-1+1 = 3+1

5a+53a=4

58a=4

Dividing both sides by the coefficient of 'a' which is 58 gives us;

58a/58 = 4/58

a = 2/29

The value of a is therefore no real number but a fraction.

-2 is the right