Henry rolls 2 number cubes numbered 1 through 6 while playing his favorite board game. he will get a second turn if he rolls a sum that is an even number less than 10. what are henry's chances of getting a second turn when he rolls the number cubes? a. seven over eighteen b.11 over 18 c.5 over 36 d.17 over 36

1. There are 6·6=36 possible outcomes of rolling two number cubes.

2. He must roll the sum 2, 4, 6, 8.

To roll 2 he has 1 chance - (1,1) {here ordered pair (i,j) means that i is the number rolled on 1st cube and j is the number rolled on 2nd cube}.

To roll 4 he has 3 chances - (1,3), (2,2) and (3,1).

To roll 6 he has 5 chances - (1,5), (2,4), (3,3), (4,2) and (5,1).

To roll 8 he has 5 chances - (2,6), (3,5), (4,4), (5,3) and (6,1).

In total 1+3+5+5=14 possible favorable outcomes.

Then his chances of getting a second turn when he rolls the number cubes are 14:36=7:18.

correct choice is A

your question is incomplete, write all the numbers in the sequence that it tells you.  

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