Two cars leave from a town at the same time traveling in opposite directions. one travels 5 mph faster than the other. in 3 hours, they are 267 miles apart. find how fast each is traveling?

Relative speed can play a major role in creating distance between two bodies. If the relative speed between two bodies is 0, then both the bodies are moving in the same direction with a similar speed. Therefore, the speed of Car A is 47 mph and the speed of Car B is 42 mph.

Let us give the names of two cars

Car A who is faster than Car B by 5 mph.

Now, let us assumed the speed of Car B be x mph.

Thus, the speed of Car A will be (x+5).

The formula for finding the distance of any body is given as:

According to the question,

In 3 hours, they are 267 miles apart.

Thus,

The distance traveled by car A in three hours will be.

The distance traveled by car B in three hours will be.

Therefore, the addition of both the distance will be equated to 267 miles because both the cars a traveled in opposite direction.

Thus,

Therefore, the speed of Car A is 47 mph and the speed of Car B is 42 mph.

To know more about relative speed, please refer to the link:

link

Let the slower cars speed equal X.

The faster cars speed would be X+5 ( 5 mph faster).

They traveled for 3 hours

Multiply the time of travel by speed to equal the number of miles traveled.

So you have:

3X + 3(X+5) = 267 miles

Simplify the left side:

3X + 3X+15 = 267

Combine like terms:

6x + 15 = 267

Subtract 15 from each side"

6x = 252

Divide each side by 6:

x = 252 / 6

X = 42

The slower car was traveling at 42 mph and the faster car was traveling at 47 mph.

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.